Cyclotomic polynomial
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In algebra, the nth cyclotomic polynomial, for any positive integer n, is the monic polynomial
| Φn(X) = | ∏ | (X − ω) |
| ω |
where the product is over all primitive nth roots of unity ω, i.e. all the complex numbers ω of order n.
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[edit] Properties
The degree of Φn, or in other words the number of factors in its definition above, is φ(n), where φ is Euler's totient function.
The coefficients of Φn are integers. In other words, ![\Phi_n(X)\in\mathbb{Z}[X].](http://upload.wikimedia.org/math/e/8/8/e883340145250b95274d5af2e973cf5f.png)
For any positive integer n we have
and (what is equivalent, by Möbius inversion)
where μ is the Möbius function.
The polynomial Φn(X) is irreducible in the ring
. This result, due to Gauss, is not trivial.[1] The case of prime n is easier to prove than the general case, thanks to Eisenstein's criterion.
If n is a prime power, say pm where p is prime, then
In particular ( for m = 1)
Any cyclotomic polynomial Φn(X) has a simple expression in terms of Φq(X) where q is the radical of n:
- Φn(X) = Φq(Xn / q)
If n > 1 is odd, then Φ2n(X) = Φn( − X).
If n has at most two distinct odd prime factors, then the coefficients of Φn are all in the set {1, −1, 0}. The converse is not true. For instance,
only has coefficients in {1, −1, 0}. The first cyclotomic polynomial having a coefficient not in this set is Φ105(X) with coefficient −2.
[edit] Examples
- Φ1(X) = X − 1
- Φ2(X) = X + 1
- Φ3(X) = X2 + X + 1
- Φ6(X) = X2 − X + 1
- Φ9(X) = X6 + X3 + 1
- Φ15(X) = X8 − X7 + X5 − X4 + X3 − X + 1
[edit] Applications
Using the fact that Φn is irreducible, one can prove the existence of a prime congruent to 1 modulo n,[citation needed] which is a special case of Dirichlet's theorem on arithmetic progressions.
[edit] See also
[edit] References
- ^ Lang, Serge (2002), Algebra, Graduate Texts in Mathematics, 211 (Revised third ed.), New York: Springer-Verlag, MR1878556, ISBN 978-0-387-95385-4





